Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 505: 2

Answer

$\dfrac{\pi}{2}$

Work Step by Step

We know that since $\cos{(\frac{\pi}{2})}=0$, then by the definition of the inverse function: $\cos^{-1}{(0)}=\frac{\pi}{2}$. (because it is in the right domain)
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