Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 505: 4

Answer

$-\dfrac{\pi}{6}$

Work Step by Step

We know that since $\sin{(-\frac{\pi}{6})}=-0.5$, then by the definition of the inverse function: $\sin^{-1}{(-0.5)}=-\frac{\pi}{6}$. (because it is in the right domain, in $[\frac{-\pi}{2},\frac{\pi}{2}]$)
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