Answer
$ -\frac{\pi}{9}$
Work Step by Step
$sin^{-1}(sin(-\frac{8\pi}{9}))=sin^{-1}(-sin\frac{8\pi}{9})=sin^{-1}(-sin\frac{\pi}{9})=-\frac{\pi}{9}$.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 505: 13
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