Answer
$0.9$
Work Step by Step
We know that $f(f^{-1}(x))=x$.
For inverse sine, the value of $x$ should be in the interval $-1 \leq x\leq 1$.
Hence, $\sin(\sin^{-1}(0.9)=0.9.$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 505: 14
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