Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 505: 10

Answer

$\dfrac{3\pi}{4}$

Work Step by Step

We know that $f^{-1}(f(x))=x$. For inverse cosine, the value of $x$ (angle measure) should be in the interval $ 0\leq x\leq \pi$. Hence, $\cos^{-1}{(\cos{(\frac{3\pi}{4}}}))=\frac{3\pi}{4}$
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