Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 505: 17

Answer

not defined

Work Step by Step

For inverse cosine, the value of $x$ should be in the interval $-1 \leq x\leq 1$. Since $-1.6 \lt-1$, hence $\cos^{-1}{(-1.6)}$ is not defined and therefore $\cos{(\cos^{-1}{\frac{x}{y}(-1.6)}})$ is not defined.
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