Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 505: 11

Answer

$-\frac{\pi}{3}$

Work Step by Step

$tan^{-1}(tan\frac{2\pi}{3})=tan^{-1}(-tan\frac{\pi}{3})=tan^{-1}(-\sqrt 3)=-\frac{\pi}{3}$.
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