Answer
$-1$
Work Step by Step
Combine the expressions to get $log_6[(x+3)(x+4)]=log_66 \longrightarrow (x+3)(x+4)=6 \longrightarrow x^2+7x+6=0 \longrightarrow (x+6)(x+1)=0 \longrightarrow x=-6,-1$. Check, $x=-1$ is the solution.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - Chapter Review - Review Exercises - Page 346: 42
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