Answer
$-3, \frac{1}{2}$
Work Step by Step
Take logarithm on both sides to get $ln2^3=(x^2)ln2^2+(5x)ln2 \longrightarrow 2x^2+5x-3=0 \longrightarrow (2x-1)(x+3)=0 \longrightarrow x=-3, \frac{1}{2}$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - Chapter Review - Review Exercises - Page 346: 40
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