Answer
$x=\frac{2\ln{3}}{\ln{5}-\ln{3}}$
Work Step by Step
If $x\ln{5}=(x+2)\ln{3}\\x\ln{5}=x\ln{3}+2\ln{3}\\x\ln{5}-x\ln{3}=2\ln{3}\\x(\ln{5}-\ln{3})=2\ln{3}\\x=\frac{2\ln{3}}{\ln{5}-\ln{3}}$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - Chapter Review - Review Exercises - Page 346: 37
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