Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - Chapter Review - Review Exercises - Page 346: 36

Answer

$x=\frac{1}{4}.$

Work Step by Step

We know that if $y=\log_a{b}$, then $a^y=b$. Hence here: $x^{-3}=64\\x^3=\frac{1}{64}\\\sqrt[3]{x^3}=\sqrt[3]{\frac{1}{64}}\\x=\frac{1}{4}.$
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