Answer
$x=\frac{1}{4}.$
Work Step by Step
We know that if $y=\log_a{b}$, then $a^y=b$.
Hence here: $x^{-3}=64\\x^3=\frac{1}{64}\\\sqrt[3]{x^3}=\sqrt[3]{\frac{1}{64}}\\x=\frac{1}{4}.$
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