Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - Chapter Review - Review Exercises - Page 346: 28

Answer

$\approx2.124$

Work Step by Step

Using the Change-of-Base Formula we know that $\log_a{b}=\frac{\log_c{b}}{\log_c{a}}$. Evaluate the given expression using a calculator to obtain: $\log_4{19}=\frac{\ln{19}}{\ln{4}}=2.12396\approx2.124.$
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