Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.6 Logarithmic and Exponential Equations - 5.6 Assess Your Understanding - Page 311: 9



Work Step by Step

The base is same on the 2 sides on the equation (and it is not $1$), hence they will be equal if the exponents are equal. Hence $\log_4{(x+2)}=\log_4{8}$ if and only if $8=x+2$, hence after subtracting 2 from both sides: $x+2-2=8-2\\x=6.$
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