Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.6 Logarithmic and Exponential Equations - 5.6 Assess Your Understanding - Page 311: 55

Answer

$\frac{ln\pi}{1+ln\pi}\approx0.534$

Work Step by Step

Take logarithm on both sides to get $(1-x)ln\pi=(x)ln(e) \longrightarrow (1+ln\pi)x=ln\pi \longrightarrow x=\frac{ln\pi}{1+ln\pi}\approx0.534$
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