Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.6 Logarithmic and Exponential Equations - 5.6 Assess Your Understanding - Page 311: 6

Answer

$x=4$

Work Step by Step

We know that if $10^x=y$, then $\log{y}=x$ and vice versa. Hence, $\log(x+6)=1$ implies $x+6=10^1=10.$ Subtracting $6$ from each side gives: $x+6-6=10-6\\ x=4$
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