Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.6 Logarithmic and Exponential Equations - 5.6 Assess Your Understanding - Page 311: 50

Answer

$\frac{ln5-ln2}{2ln5+ln2}\approx0.234$

Work Step by Step

Take logarithm on both sides to get $(x+1)ln2=(1-2x)ln5 \longrightarrow (2ln5+ln2)x=ln5-ln2 \longrightarrow x=\frac{ln5-ln2}{2ln5+ln2}\approx0.234$
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