Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.6 Logarithmic and Exponential Equations - 5.6 Assess Your Understanding - Page 311: 43

Answer

$x=\frac{\ln{10}}{\ln{2}}\approx3.322$

Work Step by Step

Take the $\log_2$ of both sides: $\log_2{(2^x)}=\log_2{10}\\ x=\log_2{10}$ We know that $\log_a{b}=\frac{\log_c{b}}{\log_c{a}}$. Hence, $x=\log_2{10}=\frac{\ln{10}}{\ln{2}}\approx3.322.$
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