Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.6 Logarithmic and Exponential Equations - 5.6 Assess Your Understanding - Page 311: 52

Answer

$\frac{ln\frac{4}{3}}{ln5+ln\frac{4}{3}}\approx0.152$

Work Step by Step

Take logarithm on both sides to get $(1-x)ln\frac{4}{3}=(x)ln5 \longrightarrow (ln5+ln\frac{4}{3})x=ln\frac{4}{3} \longrightarrow x=\frac{ln\frac{4}{3}}{ln5+ln\frac{4}{3}}\approx0.152$
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