Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.6 Logarithmic and Exponential Equations - 5.6 Assess Your Understanding - Page 311: 10



Work Step by Step

RECALL: $\log_a{b}=\log_a{c} \longrightarrow b=c$ Hence, $\log_5{(2x+3)}=\log_5{3}\longrightarrow 2x+3=3$. Solve the equation above to obtain \begin{align*} 2x+3-3&=3-3\\ 2x&=0\\ \frac{2x}{2}&=\frac{0}{2}\\ x&=0 \end{align*}
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