Answer
$f(x)=(x+2)^2-2$
See graph
Work Step by Step
We are given the function:
$f(x)=x^2+4x+2$
Complete the square:
$f(x)=x^2+4x+4-4+2=(x+2)^2-2$
We start graphing with the basic function $a(x)=x^2$.
We horizontally shift $a(x)$ by 2 units to the left to get $b(x)=(x+2)^2$.
Then we vertically shift $b(x)$ 2 units downwards to get $f(x)=(x+2)^2-2$.
We use 3 points: $(0,2),(-2,-2),(-4,2)$.