Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 2 - Functions and Their Graphs - 2.5 Graphing Techniques: Transformations - 2.5 Assess Your Understanding - Page 104: 68

Answer

$f(x)=(x-3)^2-9$ See graph

Work Step by Step

We are given the function: $f(x)=x^2-6x$ Complete the square: $f(x)=x^2-6x+9-9=(x-3)^2-9$ We start graphing with the basic function $a(x)=x^2$. We horizontally shift $a(x)$ by 3 units to the right to get $b(x)=(x-3)^2$. Then we vertically shift $b(x)$ 9 units downwards to get $f(x)=(x-3)^2-9$. We use 3 points: $(-1,7),(3,-9),(7,7)$
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