Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 13 - Counting and Probability - 13.3 Probability - 13.3 Asses Your Understanding - Page 866: 68


a) $0.45$ b)$0.75$ c)$0.9$

Work Step by Step

These events are mutually exclusive hence I can obtain the required results by simply adding the individual probabilities. We know that probability$=\frac{\text{number of favourable outcomes}}{\text{number of all outcomes}}.$ a) P(at most 2 people)=$P(0)+P(1)+P(2)=0.10+0.15+0.20=0.45$ b) P(at least 2 people)=$P(2)+P(3)+P(\geq4)=0.20+0.24+0.31=0.75$ c)P(at least 1 person)=$P(1)+P(2)+P(3)+P(\geq4)=0.15+0.20+0.24+0.31=0.9$
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