Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 13 - Counting and Probability - 13.3 Probability - 13.3 Asses Your Understanding - Page 866: 55

Answer

$0.936$

Work Step by Step

We know that $P(\text{an event happens})=1-P(\text{an event doesn't happen}).$ Hence, here (with $6.4\%=0.06$) we have $P(\text{never spent any money in gambling})=1-P(\text{spent some money in gambling})\\ P(\text{never spent any money in gambling})=1-0.064\\ P(\text{never spent any money in gambling})=0.936$
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