Answer
$\frac{1}{2}.$
Work Step by Step
We know that probability$=\frac{\text{number of favourable outcomes}}{\text{number of all outcomes}}.$
There are $3+5=8$ chips thus the probability of selecting a strike chip is: $\frac{3}{8}$ and the probability of selecting number $1$ is: $\frac{1}{8}$.
These events are mutually exclusive, hence the probability of either of them happening is the sum of their individual probabilities.
Hence: $P=\frac{1}{8}+\frac{3}{8}=\frac{1}{2}.$
