Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 13 - Counting and Probability - 13.3 Probability - 13.3 Asses Your Understanding - Page 866: 67


a) $0.57$ b)$0.95$ c)$0.83$ d)$0.38$ e)$0.29$ f)$0.05$ g)$0.78$ h)$0.71$

Work Step by Step

These events are mutually exclusive hence I can obtain the required results by simply adding the individual probabilities. We know that probability$=\frac{\text{number of favourable outcomes}}{\text{number of all outcomes}}.$ a) P(1 or 2 TV sets)=$P(1)+P(2)=0.24+0.33=0.57$ b) P(1 or more TV sets)=$P(1)+P(2)+P(3)+P(\geq4)=0.24+0.33+0.21+0.17=0.95$ c)P(3 or fewer TV sets)=$P(0)+P(1)+P(2)+P(3)=0.05+0.24+0.33+0.21=0.83$ d)P(3 or more TV sets)=$P(3)+P(\geq4)=0.21+0.17=0.38$ e)P(fewer than 2 TV sets)=$P(0)+P(1)=0.05+0.24=0.29$ f) P(fewer than 1 TV sets)=$P(0)=0.05$ g)P(1, 2 or 3 TV sets)=$P(1)+P(2)+P(3)=0.24+0.33+0.21=0.78$ h)P(2 or more TV sets)=$P(2)+P(3)+P(\geq4)=0.33+0.21+0.17=0.71$
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