## Functions Modeling Change: A Preparation for Calculus, 5th Edition

$2$
First, use the fact that $e^{\ln a}=a$ to simplify the expression to $e^{\ln3}-\ln e=3-\ln e$. Next, use the fact that $e=e^1$ and $\ln e^a=a$ to simplify $\ln e$ to $\ln e=\ln e^1=1$. Thus, $$e^{\ln 3}-\ln e=3-1=2$$