Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 5 - Logarithmic Functions - Exercises to Skills for Chapter 5 - Page 232: 1



Work Step by Step

Start with the innermost argument, $\log 10$. Since $\log 10^a=a$ and $10=10^1$, $\log10=\log10^1=1$. Therefore, $\log(\log 10)=\log(1)$ Since $1=10^{0}$, $$\log(\log 10)=\log(10^0)=0$$
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