Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 5 - Logarithmic Functions - Exercises to Skills for Chapter 5 - Page 232: 4

Answer

$-5$

Work Step by Step

Since $a^{-b}=\frac{1}{a^b}$, the expression can be rewritten as $\ln(e^{-5})$. Also, the identity that $\ln e^a=a$ can be used to simplify the expression to $\ln(1/e^5)=\ln e^{-5}=-5$
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