#### Answer

$-5$

#### Work Step by Step

Since $a^{-b}=\frac{1}{a^b}$, the expression can be rewritten as $\ln(e^{-5})$. Also, the identity that $\ln e^a=a$ can be used to simplify the expression to $\ln(1/e^5)=\ln e^{-5}=-5$

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Published by
Wiley

ISBN 10:
1118583191

ISBN 13:
978-1-11858-319-7

$-5$

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