Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 5 - Logarithmic Functions - Exercises to Skills for Chapter 5 - Page 232: 49

Answer

$x \approx 0.620$

Work Step by Step

First, subtract $5$ from both sides to get $$2\ln(6x-1)=2$$ Divide both sides by $2$ to get $$\ln(6x-1)=1$$ Since $e^a=e^b$ if $a=b$ and $e^{\ln a}=a$, the equation can be written as $$6x-1=e^1=e$$ Add $1$ to both sides to get $$6x=e+1$$ Divide both sides by $6$ to get $$x=\frac{e+1}{6}\approx0.620$$
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