## Functions Modeling Change: A Preparation for Calculus, 5th Edition

$=1$ ($x \gt 0$)
Using the fact that $\log(a/b)=\log(a)-\log(b)$, the expression simplifies to $$\log\left(\frac{10x}{x}\right)=\log(10)$$ Since $10=10^1$, the expression becomes $\log(10^1)=1$. (Note that $x > 0$ since $\log x$ has a positive $x$ value.)