Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 5 - Logarithmic Functions - Exercises to Skills for Chapter 5 - Page 232: 36



Work Step by Step

Use the fact that $\sqrt{a}=a^{\frac{1}{2}}$ to simplify the expression to $\ln (x^2+16)^\frac{1}{2}$ Since $\ln a^b=b\ln a$, the expression can be further simplified to $\frac{1}{2} \ln (x^2+16)$
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