Answer
$\frac{1}{2}\ln(x^2+16)$
Work Step by Step
Use the fact that $\sqrt{a}=a^{\frac{1}{2}}$ to simplify the expression to $\ln (x^2+16)^\frac{1}{2}$ Since $\ln a^b=b\ln a$, the expression can be further simplified to $\frac{1}{2} \ln (x^2+16)$
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 5 - Logarithmic Functions - Exercises to Skills for Chapter 5 - Page 232: 36
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