Answer
$\frac{1}{2}xy^3$
Work Step by Step
$\frac{7x^3y^6}{14x^2y^3}=(\frac{7}{14})(\frac{x^3}{x^2})(\frac{y^6}{y^3})=(\frac{/\!\!7}{2\times/\!\!7})(x^{3-2})(y^{6-3})=\frac{1}{2}xy^3$
Prealgebra (7th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321955048
ISBN 13:
978-0-32195-504-3
Appendix B - Exercise Set - Page 742: 7
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