Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Appendix B - Exercise Set - Page 742: 46

Answer

$\frac{18x^{14}}{y^{10}}$

Work Step by Step

Use the product rule and the definition of negative exponents. $(2x^{10}y^{-3})(9x^4y^{-7})=2\times9\times x^{10+4}\times y^{-3+(-7)}=18x^{14}y^{-10}=\frac{18x^{14}}{y^{10}}$
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