Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Appendix B - Exercise Set - Page 742: 21

Answer

$\frac{5}{6}$

Work Step by Step

$3^{-1}+2^{-1}=\frac{1}{3}+\frac{1}{2}=\frac{1\times2}{3\times2}+\frac{1\times3}{2\times3}=\frac{2}{6}+\frac{3}{6}=\frac{5}{6}$
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