Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Appendix B - Exercise Set - Page 742: 67

Answer

$\frac{30x^9}{y^6}$

Work Step by Step

Use the product rule and the definition of negative exponents. $(3x^{20}y^{-1})(10x^{-11}y^{-5})=3\times10\times x^{20+(-11)}\times y^{-1+(-5)}=30x^9y^{-6}=\frac{30x^9}{y^6}$
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