Answer
$\frac{a^8}{b^8}$
Work Step by Step
Use the product rule and the definition of negative exponents.
$(a^{-2}b^3)(a^{10}b^{-11})=a^{-2+10}b^{3+(-11)}=a^8b^{-8}=\frac{a^8}{b^8}$
Prealgebra (7th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321955048
ISBN 13:
978-0-32195-504-3
Appendix B - Exercise Set - Page 742: 65
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