## Prealgebra (7th Edition)

$\frac{a^8}{b^8}$
Use the product rule and the definition of negative exponents. $(a^{-2}b^3)(a^{10}b^{-11})=a^{-2+10}b^{3+(-11)}=a^8b^{-8}=\frac{a^8}{b^8}$