Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Appendix B - Exercise Set - Page 742: 40

Answer

$\frac{1}{y^7}$

Work Step by Step

Use the product rule and the definition of negative exponents, $y^{-6}\times y^{-3}\times y^2=y^{-6+(-3)+2}=y^{-7}=\frac{1}{y^7}$
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