Answer
$\frac{3}{64}$
Work Step by Step
$4^{-2}-4^{-3}=\frac{1}{4^2}-\frac{1}{4^3}=\frac{1\times4}{4^2\times4}-\frac{1}{4^3}=\frac{4}{4^3}-\frac{1}{4^3}=\frac{3}{4^3}=\frac{3}{64}$
Prealgebra (7th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321955048
ISBN 13:
978-0-32195-504-3
Appendix B - Exercise Set - Page 742: 30
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