Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.6 Events Involving Not and Or; Odds - Exercise Set 11.6: 82

Answer

10:9

Work Step by Step

The odds against E are found by taking the probability that E will not occur and dividing by the probability that E will occur. Odds against E = $\frac{P(not E)}{P(E)}$ Using the information given to us in the problem, we find the odds against selecting a comedy. E={18 comedies} P(E)= $\frac{18}{38}$ = $\frac{9}{19}$ P(not E) = 1 - P(E) = 1 - $\frac{9}{19}$ =$\frac{19 - 9}{19}$ = $\frac{10}{19}$ Odds against E = $\frac{\frac{10}{19}}{\frac{9}{19}}$ = $\frac{10}{9}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.