#### Answer

As a ratio-57:85; 85:57

#### Work Step by Step

The odds in favor of E are found by taking the probability that E will occur
and dividing by the probability that E will not occur.
Odds in Favor = $\frac{P(E)}{P(not E)}$
We are asked to find the odds in favor and the odds against a person being in the Army.
P(E)= $\frac{570000}{1420000}$ = $\frac{57}{142}$
P(not E) = 1 - P(E)
= 1 - $\frac{57}{142}$
=$\frac{142 - 57}{142}$
= $\frac{85}{142}$
Odds in Favor = $\frac{\frac{57}{142}}{\frac{85}{142}}$ = $\frac{57}{85}$
The odds against E are found by taking the probability that E will not occur
and dividing by the probability that E will occur.
Odds against E = $\frac{P(not E)}{P(E)}$
Odds against E = $\frac{\frac{85}{142}}{\frac{57}{142}}$ = $\frac{85}{57}$
The odds against E can also be found by reversing the ratio representing the
odds in favor of E.