Answer
a.) 29:71
b.) 71:29
Work Step by Step
a.) The odds in favor of E are found by taking the probability that E will occur
and dividing by the probability that E will not occur.
Odds in Favor = $\frac{P(E)}{P(not E)}$
We find the odds in favor of a child in a two-parent household having parents who are college graduates.
E: {29}
P(E) = $\frac{29}{100}$
P(not E) = 1 - P(E)
= 1 - $\frac{29}{100}$
=$\frac{100 - 29}{100}$ = $\frac{71}{100}$
Odds in Favor = $\frac{\frac{29}{100}}{\frac{71}{100}}$ = $\frac{29}{71}$
b.)The odds against E are found by taking the probability that E will not occur
and dividing by the probability that E will occur.
Odds against E = $\frac{P(not E)}{P(E)}$
Odds against E = $\frac{\frac{71}{100}}{\frac{29}{100}}$ = $\frac{71}{29}$
The odds against E can also be found by reversing the ratio representing the
odds in favor of E.