#### Answer

61:10; 10:61

#### Work Step by Step

The odds in favor of E are found by taking the probability that E will occur
and dividing by the probability that E will not occur.
Odds in Favor = $\frac{P(E)}{P(not E)}$
Find the odds in favor and the odds against a person in the military population being a man.
P(E)= $\frac{1220000}{1420000}$ = $\frac{122}{142}$ = $\frac{61}{71}$
P(not E) = 1 - P(E)
= 1 - $\frac{61}{71}$
=$\frac{71 - 61}{71}$
= $\frac{10}{71}$
Odds in Favor = $\frac{\frac{61}{71}}{\frac{10}{71}}$ = $\frac{61}{10}$
The odds against E are found by taking the probability that E will not occur
and dividing by the probability that E will occur.
Odds against E = $\frac{P(not E)}{P(E)}$
Odds against E = $\frac{\frac{10}{71}}{\frac{61}{71}}$ = $\frac{10}{61}$
The odds against E can also be found by reversing the ratio representing the
odds in favor of E.