#### Answer

3:68; 68:3

#### Work Step by Step

The odds in favor of E are found by taking the probability that E will occur
and dividing by the probability that E will not occur.
Odds in Favor = $\frac{P(E)}{P(not E)}$
Find the odds in favor and the odds against a person in the population being a woman in the Air Force.
P(E)= $\frac{60000}{1420000}$ = $\frac{6}{142}$
P(not E) = 1 - P(E)
= 1 - $\frac{6}{142}$
=$\frac{142 - 6}{142}$
= $\frac{136}{142}$
Odds in Favor = $\frac{\frac{6}{142}}{\frac{136}{142}}$ = $\frac{6}{136}$ = $\frac{3}{68}$
The odds against E are found by taking the probability that E will not occur
and dividing by the probability that E will occur.
Odds against E = $\frac{P(not E)}{P(E)}$
Odds against E = $\frac{\frac{136}{142}}{\frac{6}{142}}$ = $\frac{68}{3}$
The odds against E can also be found by reversing the ratio representing the
odds in favor of E.