Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.6 Events Involving Not and Or; Odds - Exercise Set 11.6 - Page 736: 81



Work Step by Step

The odds against E are found by taking the probability that E will not occur and dividing by the probability that E will occur. Odds against E = $\frac{P(not E)}{P(E)}$ Using the information given to us in the problem, we find the odds against selecting a history. E={10 histories} P(E)= $\frac{10}{38}$ = $\frac{5}{19}$ P(not E) = 1 - P(E) = 1 - $\frac{5}{19}$ =$\frac{19 - 5}{19}$ = $\frac{14}{19}$ Odds against E = $\frac{\frac{14}{19}}{\frac{5}{19}}$ = $\frac{14}{5}$
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