Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.6 Events Involving Not and Or; Odds - Exercise Set 11.6 - Page 736: 49

Answer

$\frac{85}{142}$

Work Step by Step

The probability that an event E will not occur is equal to 1 minus the probability that it will occur. P(not E)= 1 - P(E) Find the probability that a person randomly selected from the military population is not in the army. P(is not in the Army) = 1 - P(is in the Army) P(is in the Army) = $\frac{570000}{1420000}$ = $\frac{57}{142}$ P(is not in the Army) = 1 - $\frac{57}{142}$ = $\frac{142 - 57}{142}$ = $\frac{85}{142}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.