## Thinking Mathematically (6th Edition)

$\frac{1}{2}$
P(E) = $\frac{no.\ of\ outcomes\ in\ favor}{Total\ no.\ of\ outcomes}$ It is equally probable that the pointer will land on any one of the ten colored regions, and we spin again if we land on a borderline. There are 10 total regions. E: A region that is brown or yellow. Favorable outcomes= {3 Regions of Brown and 2 Regions of Yellow} P(E) = $\frac{5}{10}$ = $\frac{1}{2}$