## Thinking Mathematically (6th Edition)

P(E) = $\frac{no.\ of\ outcomes\ in\ favor}{Total\ no.\ of\ outcomes}$ A single die is rolled twice. The 36 equally likely outcomes are shown in the attached picture. E: two numbers whose sum is less than 13. Since the greatest number is 6, if we add 6 from both the outcomes, we find that the maximum value is 12. Therefore, all outcomes are favorable. Favorable outcomes= {all} P(E) = $\frac{36}{36}$ =1