Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.4 Fundamentals of Probability - Exercise Set 11.4 - Page 716: 40



Work Step by Step

P(E) = $\frac{no.\ of\ outcomes\ in\ favor}{Total\ no.\ of\ outcomes}$ A single die is rolled twice. The 36 equally likely outcomes are shown in the attached picture. E: two numbers whose sum is less than 13. Since the greatest number is 6, if we add 6 from both the outcomes, we find that the maximum value is 12. Therefore, all outcomes are favorable. Favorable outcomes= {all} P(E) = $\frac{36}{36}$ =1
Small 1501352441
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.