#### Answer

$\frac{3}{8}$

#### Work Step by Step

P(E) = $\frac{no.\ of\ outcomes\ in\ favor}{Total\ no.\ of\ outcomes}$
If M represents a male child and F represents a female child, the set of equally likely outcomes for the children’s genders when three children are selected is:
S = {MMM, MMF, MFM, MFF, FMM, FMF, FFM, FFF}.
E: Exactly two male children
Favorable outcomes= {MMF, FMM, MFM}
P(E) = $\frac{3}{8}$