#### Answer

$\frac{3}{4}$

#### Work Step by Step

P(E) = $\frac{no.\ of\ outcomes\ in\ favor}{Total\ no.\ of\ outcomes}$
Given that H is heads and T is tails, the set of equally likely outcomes is:
S = {HH, HT, TH, TT}.
E: Getting at least one head.
Favorable outcomes= {TH, HH, HT}
P(E) = $\frac{3}{4}$