#### Answer

$\frac{1}{4}$

#### Work Step by Step

P(E) = $\frac{no.\ of\ outcomes\ in\ favor}{Total\ no.\ of\ outcomes}$
A single die is rolled twice. The 36 equally likely outcomes are shown in the attached picture.
E: two odd numbers
Favorable outcomes= {(1,1),(1,3),(1,5),(3,1),(3,3),(3,5),(5,1),(5,3),(5,5)}
P(E) = $\frac{9}{36}$ = $\frac{1}{4}$